find the Vertical Asymptote;
r(x) = 1/(a-(x-b)^2)
Assuming a and b are 0
i got 2b and (a-b^2) as answers but they are wrong.

Any help? This is for my Calculus class, and we are working on Family of Functions, if that helps.

Question

find the Vertical Asymptote;
r(x) = 1/(a-(x-b)^2)
Assuming a and b are >0
i got 2b and (a-b^2) as answers but they are wrong. 

Any help? This is for my Calculus class, and we are working on Family of Functions, if that helps.

solomonzelman · Answer

At which values of x is the denominator equal to zero?

solomonzelman · Answer

$\large\color{black}{ \displaystyle a-(x-b)^2=0 }$

$\large\color{black}{ \displaystyle a=(x-b)^2 }$

$\large\color{black}{ \displaystyle \pm\sqrt{a}=x-b }$

$\large\color{black}{ \displaystyle b\pm\sqrt{a}=x }$

anonymous · Answer

thank you! i was expanding the equation

solomonzelman · Answer

I didn't think that finding asymptotes is calculus, but in any case I hope that helped :)