Question

What is the sum of the roots of the following equation?
3x^2 − 24 = 6x

(A) −4
(B) −2
(C) 2
D) 4

Answer 1

ok so 3x^2-6x-24=0
use the quadratic formula http://www.statisticslectures.com/images/quadeq1.gif

(6+-sqrt(6^2+4*24*3))/6=(6+-18)/6=-2, 4

-2+4=2

Answer 2

\(\Huge\text{Welcome to OpenStudy!!!}\)

Answer 3

i don't get this part
(6+-sqrt(6^2+4*24*3))/6=(6+-18)/6=-2, 4

Answer 4

it doesn't pop up properly

Answer 5

Ponder: \((x-a)(x-b) = x^{2} + (a+b)x + ab\)

Answer 6

how do i do that?

Answer 7

Subtract 6x