6. Evaluate the following expression: 1 + 3 + 5 + ... + 35 + 37.
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OpenStudy (anonymous):
(A) 361
(B) 362
(C) 324
(D) 323
imqwerty (imqwerty):
this is an arithmetic progression [AP]
do u know how to calculate the summation of an AP?
imqwerty (imqwerty):
not here rhett
OpenStudy (anonymous):
ok sorry
imqwerty (imqwerty):
e.e
its k
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OpenStudy (anonymous):
no i don't
imqwerty (imqwerty):
ok theres a formula used to find the summation
imqwerty (imqwerty):
do u remember any such formula?
OpenStudy (anonymous):
something with n and +1 I'm not sure
imqwerty (imqwerty):
ok the formula is this-
\[S=\frac{ n }{ 2 }\left( 2a+(n-1)d \right)\]
S=summation :) that is the sum
n=number of terms
a=1st term
d=common difference
:)
now your work is to find ->n,a,d
and then put them in this equation to get S
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OpenStudy (anonymous):
is there any other formula that's easier to remember
imqwerty (imqwerty):
yes
u can also do it like this-
\[S=\frac{ n }{ 2 }(a+l)\]
here
S=summation
n=number of terms
a=1st term
l=last term
OpenStudy (anonymous):
i got something different
imqwerty (imqwerty):
what did u get?
OpenStudy (anonymous):
703
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imqwerty (imqwerty):
which method did u choose?
OpenStudy (anonymous):
2nd
imqwerty (imqwerty):
ok what values of n,a,l did u get?
OpenStudy (anonymous):
n=37
A=1
l=37
imqwerty (imqwerty):
how did u get n=37 ?
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OpenStudy (anonymous):
cuz there are 37 terms right?
OpenStudy (anonymous):
still there?
OpenStudy (anonymous):
anyone?
OpenStudy (anonymous):
Refer to the attachment created with the Mathematica computer program.