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Mathematics 16 Online
OpenStudy (anonymous):

Simplify the expression ( 4x^2y^3)^3

OpenStudy (alekos):

are you familiar with the exponent rules?

OpenStudy (anonymous):

no :(

OpenStudy (alekos):

OK so if we distribute the cube at the end we get (4^3)[(x^2)^3][(y^3)^3] OK?

OpenStudy (anonymous):

ok :?

OpenStudy (alekos):

is that a "no I don't understand" ?

OpenStudy (anonymous):

i do

OpenStudy (alekos):

OK so lets do the first part. What's 4^3

OpenStudy (anonymous):

64

OpenStudy (anonymous):

right?

OpenStudy (alekos):

very good! and now what is (x^2)^3

OpenStudy (anonymous):

dont know.-.

OpenStudy (alekos):

ok then here is one of the rules (x^m)^n = x^mn

OpenStudy (anonymous):

wait is the answer 64x^6y^9?

OpenStudy (alekos):

yes! well done!!

OpenStudy (alekos):

gotta go

OpenStudy (anonymous):

thank you:)

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