Question

Consider the line
y=−5/3x+1
.

Find the equation of the line that is parallel to this line and passes through the point
6, 3
.

Find the equation of the line that is perpendicular to this line and passes through the point
6, 3

Answer 1

um ull haft to look it up caz theres a million ways

Answer 2

A: parallel lines have same slopes. the slope of given line is -5/3. thus the slope of line parallel to it is also -5/3.

now we have y=-5/3x+b.
substitute the given coordinate: 3=-5/3*6 + b
b=3+10
b=13

thus the equation is y=-5/3x+13

Answer 3

B: perpendicular lines have negative reciprocal slopes. the slope of given line is -5/3. thus the slope of line perpendicular to it is 3/5.

now we have y=3/5x+b
substitute given point: 3=3/5*6+b
b=-0.6

thus the equation is y=3/5x-0.6