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OpenStudy (anonymous):
i need help!!!
Please
If f(x)=2x^2-x-6 and g(x)=
x^2-4, find f(x)/g(x)
Answers:
2x+3/x-2
2x-3/x+2
2x+3/x+2
2x-3/x-2
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OpenStudy (zpupster):
if you factor these one might cancel
OpenStudy (anonymous):
I dont get it @zpupster
OpenStudy (zpupster):
2x^2-x-6/x^2-4
here we see the denominator is the difference of 2 squares
x^2-4= (x-2)(x+2)
2x^2-x-6 what does this factor into?
OpenStudy (anonymous):
umm 3x^2-6?
im not good in math at al please dont laugh lol @zpupster
OpenStudy (zpupster):
step by step
(2x (x
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OpenStudy (zpupster):
(2x 3) (x 2) we need to find the signs
OpenStudy (anonymous):
but dont we have to pair them up @zpupster
OpenStudy (zpupster):
(2x -3) (x +2) = 2x^2 + x -6 that is not right so switch the signs
(2x +3) (x -2) = 2x^2 - x -6 that is right
OpenStudy (zpupster):
(2x +3) (x -2)/(x+2)(x-2) what cancels???
OpenStudy (anonymous):
ohh okay i kinda get it now @zpupster
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OpenStudy (anonymous):
one of the the (x-2) canaels right? @zpupster
OpenStudy (anonymous):
cancels*
OpenStudy (zpupster):
yes you can see your answer now. I ma sorry I had to leave yesterday.
OpenStudy (anonymous):
thank you its okay @zpupster
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