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If a parabola's focus is at (−2, 5) and the directrix is at y = −1, what is the equation representing this parabola? x2 + 4x − 12y + 67 = 0 x2 − 28 = 0 x2 − 4x + 12y − 28 = 0 x2 + 4x − 12y + 28 = 0
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@Michele_Laino @pooja195 @Hero @triciaal
you can use the definition of a parabola
distance ( -2,5) ( x,y) = distance ( ( x,y) , ( x, -1) )
|dw:1447114934973:dw|
y = 1/12 ( (x+2)^2 + 24) 12y = (x+2)^2 + 24 12y = x^2 + 4x + 4 + 24 x^2 + 4x - 12y +28= 0
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