7x+2 = x√5 Can anyone walk me through this thanks
the right side is x times the square root of 5 ?
or is it xTH root of 5?
Yeah
the first or the second?
It is x times the square root of 5
Example. \(\large\color{black}{ \displaystyle 8\cdot x+5 =\sqrt{19}\cdot x }\) \(\large\color{black}{ \displaystyle 8\cdot x-\sqrt{19}\cdot x+5 =0 }\) \(\large\color{black}{ \displaystyle (8-\sqrt{19})\cdot x+5 =0 }\) \(\large\color{black}{ \displaystyle (87-\sqrt{19})\cdot x=-5 }\) \(\large\color{black}{ \displaystyle x=-5/(8-\sqrt{19}) }\)
im sorry im lost what did u do
did u factor
I subtracted the (√19)•x, then I factored the first two things out of x, then subtracted five from both sides, then divided by 8-(√19), {or by x's coefficient}, on both sides.
is there any other way
is there any other way
what I did isn't that difficult (?)
write all x terms leftside and constants right side
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