Mathematics
9 Online
OpenStudy (youngnephew34):
what is the value of x in the diagram?
A) 15
B ) 5 2/5
C) 19
D) 3/5
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OpenStudy (anonymous):
Diagram?
OpenStudy (youngnephew34):
ok
OpenStudy (youngnephew34):
OpenStudy (youngnephew34):
I put in the diagram
OpenStudy (youngnephew34):
so you do 15+25
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OpenStudy (youngnephew34):
or would you do 15x2
OpenStudy (youngnephew34):
so you doing 15x15
OpenStudy (anonymous):
yes because 15x15 is the same thing as 15^2
OpenStudy (youngnephew34):
so it will be 225=625
OpenStudy (anonymous):
Hold on let me check everything first
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OpenStudy (anonymous):
Sorry man didnt see the 25 was the hypotenuse(C)
What I meant was 25^2-15^2=B^2
OpenStudy (anonymous):
When you get B^2, you find the square root of that, You do the same thing there, but this time its B^2+9^2=X^2 The finally square root of X
OpenStudy (youngnephew34):
9x9=81
OpenStudy (anonymous):
yes
OpenStudy (youngnephew34):
ok I got a different question
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OpenStudy (anonymous):
What is it
OpenStudy (youngnephew34):
when you do 625-225=400 and you try 400x400160000
OpenStudy (youngnephew34):
do you do 160000=81
OpenStudy (youngnephew34):
I mean 160000+81
OpenStudy (anonymous):
No after you get 400 you have to find the square root of 400
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OpenStudy (youngnephew34):
oh ok
OpenStudy (youngnephew34):
it's 20
OpenStudy (youngnephew34):
so you will do 40+81
Directrix (directrix):
Use the attached theorem to get:
x is to 25 as 9 is to 15
x / 25 = 9 / 15
Solve that for x.
OpenStudy (youngnephew34):
121/25 gave me 4.84
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OpenStudy (anonymous):
But you really dont have to yet, because then you have to use 20^2*9^2=C^2
Directrix (directrix):
The triangle is not a right triangle. There is no hypotenuse or right angle. The Pythagorean Theorem does not apply here.
OpenStudy (anonymous):
I thought so
OpenStudy (anonymous):
I sort of doubted it
OpenStudy (youngnephew34):
40x81 right or nah
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OpenStudy (anonymous):
dont think so
Directrix (directrix):
Solve this for x:
|dw:1447120695827:dw|