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Mathematics
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Sqrt 4xy^3 * sqrt 6y
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\[\text{i suppose the question is to simplify?!}\]
Yes it's simplify sorry
\[\sqrt{4xy^3}\times \sqrt{6y}\] first use one property of radicals \[\sqrt{4xy^3}\times \sqrt{6y}=\sqrt{4xy^36y}\]
this the property \[\sqrt{a}\sqrt{b}=\sqrt{ab}\]
now we have \[=\sqrt{4xy^46}=2y\sqrt{6x}\]
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can you tell me where 2 came from and also y?
Square root of 4=2
yes that's correct
4 is a perf square so it can be simplified
and also \[\sqrt{y^4} =y^2\] y^4 is perfect square too
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i realized i made a mistake above should have gotten \[2y^2\sqrt{6x}\]
Thank you can you stay and help? I'm taking online classes and don't have much help
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