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solve log(x+9) -logx = 3 I know the - is division so, x/ (x+9)
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base ten right?
Yeah I thinks so
\(\large\color{black}{ \displaystyle \log(x+9) -\log x = 3 }\) \(\large\color{black}{ \displaystyle \log\left(\frac{x+9}{ x}\right) = 3 }\) Yes, that is right
\(\large\color{black}{ \displaystyle \log_{10}\left(\frac{x+9}{ x}\right) = 3\quad \Rightarrow \quad \left(\frac{x+9}{ x}\right)=10^3}\)
And 10^3 is 1000
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yes
So what do I do next?
\(\large\color{black}{ \displaystyle \frac{x+9}{ x}=1000 }\) solve for x.
Just using algebra, you can solve for x easily.
1000/9 = 111.111 so its just 111?
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no
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