Algebra
11 Online
OpenStudy (joshoyen):
HELP
Solve by factoring.
5x^2+47x+56=0
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OpenStudy (xapproachesinfinity):
use the ac method
5x56=280
find the factor of 280 that sum up to 47
OpenStudy (joshoyen):
hmm, im still confused :L
OpenStudy (joshoyen):
oh wait
is it 7 x 40
OpenStudy (xapproachesinfinity):
will any second degree poly can be written like a(x+b)(x+c)
the goal here is to a,b,c
OpenStudy (xapproachesinfinity):
but ac method don't worry about a just b and c
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OpenStudy (xapproachesinfinity):
yes that is correct
OpenStudy (xapproachesinfinity):
40x7=280
and 40+7=47
good
OpenStudy (xapproachesinfinity):
now lets rewrite the equation \[5x^2+47x+56=5x^2+40x+7x+56=(5x^2+40)+(7x+56)\]
OpenStudy (xapproachesinfinity):
now what you can see is 5x^2and 40x have 5x in common
OpenStudy (xapproachesinfinity):
error in parenthesis i should have (5x^2+40x) not (5x^2+40)
forget x
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OpenStudy (xapproachesinfinity):
and we can also see that 7x and 56 have 7 in common (common factor)
so we can now do this
\[=5x(x+8)+7(x+8)=(5x+7)(x+8)\]
OpenStudy (xapproachesinfinity):
so we got (5x+7)(x+8)
OpenStudy (joshoyen):
ohhhh , okay now i get it
OpenStudy (joshoyen):
alright thankyou!
OpenStudy (xapproachesinfinity):
you welcome
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OpenStudy (joshoyen):
wait can we do one more equation?
OpenStudy (joshoyen):
7a^2 - a - 8 = 0