Question

HELP HOW DO I SOLVE THIS PROPORTION???

Answer 1

put your question here

Answer 2

Cross multiply, then solve for y.

Answer 3

ok i did that but idk if its right

Answer 4

i got 15y-40=12y but idk what to do next

Answer 5

Add like terms. Solve for y. Try to get y on one side of the equation by itself.

Answer 6

-40=-3y?

Answer 7

Sure. Now divide -40 by -3.

Answer 8

13.3?

Answer 9

theres no option for that only 3/40 and 40/3 is it 40/3?

Answer 10

40/3 is the exact answer. 13.3 is the approximate value.

Answer 11

ok thanks can you help with other ones?

Answer 12

I've got my own homework, so it depends. Can you make it quick?

Answer 13

yes

Answer 14

find x

Answer 15

Two similar shapes. So set the proportions equal to each other. It's read like an analogy "8 is to 12 as 6 is to x," only in mathematical form, it's written as a proportion. To wit:

\[\frac{ 8 }{ 12 } = \frac{ 6 }{ x }\]

Solve for x and you're done.

Answer 16

ok thsnks so is it 8x= 72

Answer 17

so is it 9?

Answer 18

i have one more problem!

Answer 19

Same as with the trapezoids, except you don't know the hypotenuse of the larger triangle. This is easy enough to find using Pythagorean's Theorem a^2+b^2 = c^2.

First, you find the left hand side of the smaller triangle, which can be found using
x^2 + y^2 = 10^2, y being the tall arm of the triangle. So y = sq. root(100 - x^2). Keep in mind that the y for the left triangle is the same as the y for the large triangle (on the right hand side). Use this knowledge to solve for the hypotenuse of the larger triangle. After that, it's as simple as using the proportion method I showed you before with the trapezoids.

Answer 20

sorry i really dont understnad this one can you work out the first part then let me finish?

Answer 21

i really need help fast!

Answer 22

I gave you everything you need to solve the problem. What part are you having trouble understanding?

Answer 23

how to set it up to solve

Answer 24

Can you be a bit more specific than that? I mean, that's exactly what I told you how to do in the paragraph above. If you want me to help that's what I'll do, but I'm not going to do your homework for you. Think it through a little. I know you can do it.