Question

Triangle ABC has side lengths: √6, √2, and 2√2 units.
If the base of the triangle has a length of √6, what is the measure of the base angle?
I'm not entirely sure which base angle the question is talking about. Thanks!

Answer 1

\[a= \sqrt{6}, b= \sqrt{2}, c= 2\sqrt{2}\]

Answer 2

this is a right triangle. because side lengths obey pythsgoras theorem

(2root(2))^2 = 6 + 2
8 = 8

Answer 3

\[\cos A = \frac{ b ^{2}+c ^{2}-a ^{2} }{ 2bc}\]

Answer 4

u r right
I used above formula

Answer 5

sorry . it is cosx. not sinx.

so cosx = root(3)/2
x = 30 degrees :)

Answer 6

Thank you so much!! @lochana @dayakar