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Mathematics 22 Online
OpenStudy (youngnephew34):

What are the values of x and y? A) x=2 square root of 3, y=4 B) x=8 square root of 7, y=4 square root of 21 C) x= 8 square root of 3, y= 8 square root of 3 D) x= 4 square root of 21, y= 8 square root of 7 Someone PLZZZZZZ HELLPPPPP MEEE FAN AND MEDAL

OpenStudy (youngnephew34):

OpenStudy (youngnephew34):

No one is willing to help

OpenStudy (anonymous):

i'll try

OpenStudy (youngnephew34):

ok

OpenStudy (youngnephew34):

you still there

OpenStudy (anonymous):

yeah.......just calculating

OpenStudy (youngnephew34):

oh ok

OpenStudy (anonymous):

dude.....I tried but I got weird answers....

OpenStudy (youngnephew34):

like what

OpenStudy (anonymous):

Wait......what grade you in......that could help?

OpenStudy (youngnephew34):

11

OpenStudy (anonymous):

ok......

OpenStudy (youngnephew34):

yea

OpenStudy (dayakar):

by similar triangles property D is the answer do u want explanation

OpenStudy (youngnephew34):

yes

OpenStudy (dayakar):

|dw:1447164038146:dw|

OpenStudy (dayakar):

figure separated as two triangle observe carefully

OpenStudy (youngnephew34):

ok

OpenStudy (dayakar):

both are right angled triangles

OpenStudy (youngnephew34):

yea

OpenStudy (dayakar):

angle 2 is same in two triangles

OpenStudy (dayakar):

is it clear

OpenStudy (youngnephew34):

yes

OpenStudy (dayakar):

so two triangles are similar (AA property)

OpenStudy (dayakar):

so corresponding sides are proportional

OpenStudy (youngnephew34):

but I'm still trying to figure how did you get d

OpenStudy (bluebeta):

I can see your picture on here, but not the other site? strange.

OpenStudy (dayakar):

i'm to the point wait

OpenStudy (youngnephew34):

ok

OpenStudy (dayakar):

\[\frac{ 28 }{ x }=\frac{ x }{ 12 }\]

OpenStudy (youngnephew34):

so you divide

OpenStudy (youngnephew34):

no cross multiply

OpenStudy (dayakar):

do the cross multiplication

OpenStudy (youngnephew34):

so 28x12=336

OpenStudy (dayakar):

yes

OpenStudy (youngnephew34):

so you would do the sure root

OpenStudy (youngnephew34):

I meant square

OpenStudy (dayakar):

\[x ^{2}=28 *12\]

OpenStudy (youngnephew34):

so you going to do 336^2

OpenStudy (dayakar):

\[x= \sqrt{7*(4 * 4)*3}\]

OpenStudy (dayakar):

is it clear

OpenStudy (youngnephew34):

I don't get that part how did you do that

OpenStudy (dayakar):

28 =7*4 12=4*3

OpenStudy (youngnephew34):

So you would multiply all of those

OpenStudy (dayakar):

no

OpenStudy (dayakar):

4 comes out side removing root

OpenStudy (dayakar):

\[x= 4\sqrt{7*3}\]

OpenStudy (youngnephew34):

4 square root of 21

OpenStudy (dayakar):

yea

OpenStudy (youngnephew34):

oh ok

OpenStudy (dayakar):

may i leave

OpenStudy (youngnephew34):

yes

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