Mathematics
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OpenStudy (lisa123):
Find all the rational zeros of the function.
x^3-31x-30
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OpenStudy (dayakar):
let p(x) =x^3-31x -30
find p(-1)
OpenStudy (lisa123):
0
OpenStudy (lisa123):
p(x)=0
OpenStudy (dayakar):
right
(x-1) is a factor of p(x)
OpenStudy (dayakar):
divide p(x) with (x-1)
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OpenStudy (lisa123):
how did you know to use -1?
OpenStudy (dayakar):
sum of the coefficients odd powers x = sum of the coefficients even powers of x
then x-1 is a factor
OpenStudy (dayakar):
is it clear
OpenStudy (dayakar):
what happens
OpenStudy (lisa123):
can you use the rational roots theorem?
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OpenStudy (dayakar):
is it remainder theorem
OpenStudy (lisa123):
no I mean to find all the possible roots
OpenStudy (dayakar):
ok ,
can u divide given expression with (x-1)
OpenStudy (dayakar):
sorry divide with x+1
OpenStudy (lisa123):
yes
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OpenStudy (dayakar):
write the answer
OpenStudy (lisa123):
x^2-x-30
OpenStudy (dayakar):
very good
OpenStudy (dayakar):
now split middle term
x^2-6x+5x-30
OpenStudy (dayakar):
x(x-6)+5(x-6)
=(x-6)(x+5)
these are other two factors
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OpenStudy (lisa123):
so all of the factors are -1,6,-5, 0 ?
OpenStudy (dayakar):
p(x)= x^3-31x-30
=(x+1)(x^2-x-30)
+(x+1)(x-6)(x+5)
OpenStudy (dayakar):
x+1,(x-6),(x+5) are factors
OpenStudy (dayakar):
-1, 6 and -5 are roots
OpenStudy (dayakar):
is it clear
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OpenStudy (lisa123):
Yea thank you @dayakar