anyone really good with geometry who can explain something to me?
You should multiply each coordinate value by 2/5 to get the coordinates of the new image.
how is it eaxactly? like can you show me the steps?
like do i multiply it with the L coordinate pair? and is it cross multiplication?
FLVS student taking geometry? I'm taking geometry too and i'm in FLVS
same i'm reviewing for a DBA
Module 4?
correct dilations
I'm an honors student maybe I could help I'm on module 7 right now
the lesson is a bit complicated when they get to the graphing
really? 0.0
What assignment is this?
4.01
What do you need help with?
i wanna review what exactly is it that you do to find the l' of l on a graph?
like is it a formula or?
Hold on let me open it up
ok :)
What's the question?
Say the coords of one point is (-2,4) multiply both terms by 2/5. (-2*2/5,4*2/5) simplifies to (-4/5, 8/5)
do this for all of the points in the figure
2/5 is the scale factor right?
yes
so i multiply the original coordinates with the scale factor and that gives me the prime coordinates?
yes
It works with negative scale factors aswell
let me practice this and you guys tell me if im ok or not :3
ok
|dw:1447178660007:dw|
((SORRY IT TOOK A WHILE THE SITE WAS LAGGING :P))
((it better not kick me out again sorry for the wait)) ok lets say point A= (5,2) point B = (3,6) and point C= (2,5)
and lets say the scale factor is 3/5
so I multiply like th
lets say the question is : find the prime of point A. so A= (5,2) is multiplied to the scale factor 3/5 I do that like this? : 5/1 * 3/5 = 3 and I also multiply it by the y-value as well? like this? : 2/1 * 3/5= 6/5 what do I do with 3 and 6/5 ? I think i'm doing it wrong
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