Question

TRIG
Convert the equation to polar form.
1. x^2-y^2 = 1

Answer 1

i got this so far.
r^(2)cos^(2)theta - r^(2)sin^(2)theta = 1
r^(2)[cos^(2) theta - sin^(2)theta] = 1
r^(2) = 1/[cos^(2) theta - sin^(2)theta]
r = √(1/[cos^(2) theta - sin^(2)theta])
r = 1/ √(cos^(2) theta - sin^(2)theta)
Is this correct?

Answer 2

@IrishBoy123
wait! I thought you were replying