Solve for each system of equations
2x + 3y = 10, 3x + 2y = 5

Question

Solve for each system of equations
2x + 3y = 10, 3x + 2y = 5

anonymous · Answer

u know how to solve it?

anonymous · Answer

No idea.

anonymous · Answer

there are two way to do it, subtitution and elimination
u know any of it?

anonymous · Answer

nope, i never learned any of it. I was homeschooled from 5th-12th grade. 
and it was some stupid books that taught me nothing so i've been tying to teach myself everything on my own, and yeah.

anonymous · Answer

okay, so substitution is just changing one of the variable value, like your previous question

anonymous · Answer

and elimination is yeah it eliminate one of the variable

anonymous · Answer

$$2x+3y=10$$$$2x=-3y+10$$$$x=-\frac{ 3 }{ 2 }y +\frac{ 10 }{ 2 }$$

anonymous · Answer

that the substitute value of X, so just change X with that

triciaal · Answer

@ArifL 2 other methods are using matrix and graphing

anonymous · Answer

yeah, but it will be abit complex for matrix

anonymous · Answer

(4x - 6)(6x - 4)

A. 24x^2 + 24x + 24
B. 24x^2 - 52x + 24
C. 24x^2 + 52x -24
D. None of these 
 so what would this be?

anonymous · Answer

$$(ab) \times (cd) = ac+ad+bc+bd$$

anonymous · Answer

and thanks for reminding me @triciaal

anonymous · Answer

(-1,4)

triciaal · Answer

welcome

anonymous · Answer

and its B