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what is the equation of a line with a slope of -3 that passes through the point (3,-3)?
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We can write the equation of the line as: \[(y-b)=m(x-a)\] where m = the slope, and a and b are the coordinates (a,b)
So all that you have to do is substitute: m = -3 a = 3 b = -3 into: (y-b)=m(x-a)
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