The perimeter of a rectangle is given by P = 2W + 2L where W is the width and L is the length. The length of a rectangle is 3 more than twice its width. The perimeter of the rectangle is 66 meters. What is the length and width of the rectangle?
I need help
hint: "The length of a rectangle is 3 more than twice its width." means that L = 2W + 3 know where to go from there?
no still
ok, L = 2W + 3 means we can replace "L" with "2W + 3" wherever L shows up
still confusing
so we go from P = 2W + 2L to P = 2W + 2(2W+3) and solve for W
P= 2W+4W+6 P=6w+6
good, and we know that P = 66 so 66 = 6W + 6 what does W equal?
66=6w+6 -6 -6 60/6=6w/6 10=w
good, so that means W = 10, which is the width to find length, we go back to our other equation L = 2W + 3 if W = 10, what is L?
L=2(10) + 3 L=20+3 L=23
good, so width = 10 and length = 23 and that's all
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