If a line with a slope of 4 crosses the y-axis at (0, 1), what is the equation of the line?

y − 4x = 1

y + 4x = 1

x − 4y = 1

x + 4y = 1

Question

If a line with a slope of 4 crosses the y-axis at (0, 1), what is the equation of the line?

y − 4x = 1

y + 4x = 1

x − 4y = 1

x + 4y = 1

anonymous · Answer

the slope-intercept form of your line is y=ax+b
a is the slope, which is given. so y=4x+b
b is the y-intercept which is also given. the point (0, 1) means that line intrecpts y-axis when y=1

so the function is y=4x+1
now subtract 4x from both sides and get you answer

anonymous · Answer

it will be y - 4x=1