Question

each of the squares in the figures shown have the same area, and each of the triangles has the same area. the total area of figure A is 141cm2. the total area of figure B is 192cm2. what Is the area of each square and triangle

Answer 1

Here are the figures

Answer 2

Let

A = area of figure A
B = area of figure B
S = area of one square
T = area of one triangle


Since ` the total area of figure A is 141cm2` and because figure A has 1 square & 4 triangles, we can say


A = (one square area) + 4*(one triangle area)
141 = (S) + 4*(T)
141 = S + 4T


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we're also told that `the total area of figure B is 192cm2`. Since figure B has 2 squares and 2 triangles, we know


B = 2*(one square area) + 2*(one triangle area)
192 = 2*(S) + 2*(T)
192 = 2S + 2T

Answer 3

So we have this system of equations
141 = S + 4T
192 = 2S + 2T


which is equivalent to this system
S+4T = 141
2S+2T = 192

Answer 4

Let me know if you need help solving that system.

Answer 5

thank you