Last question of the night will probably be a really quick question just need some reassurance.

Two students, Ann and Max, factored the trinomial 4x^2 − 6x − 4. Ann factored it as 2(x − 2)(2x + 1) and Max factored it as (x − 2)(4x + 2). Indicate which student factored the trinomial completely and which student did not, and explain why.

Question

Last question of the night will probably be a really quick question just need some reassurance.

Two students, Ann and Max, factored the trinomial 4x^2 − 6x − 4. Ann factored it as 2(x − 2)(2x + 1) and Max factored it as (x − 2)(4x + 2). Indicate which student factored the trinomial completely and which student did not, and explain why.

sedatefrog712 · Answer

@Vocaloid i believe Ann factored it completely but im not completely sure

sedatefrog712 · Answer

this is what i got so far from working it out 
2(2x^2-3x-2)
2(2x^2-4-1-2)

sedatefrog712 · Answer

im not completely sure what to do next

directrix · Answer

4x^2 − 6x − 4 =

2(2x^2-3x-2) =          

2 ( 2x^2 -4x+1x-2) =     you want two numbers that multipy to -4 and add to  -4

sedatefrog712 · Answer

so -2*2=-4 and -2+-2 = -4

directrix · Answer

2 ( 2x^2 -4x+1x - 2) =

2 [ 2x (x -2) + 1* (x - 2)] =     (x -2 is a common factor

2 * (x - 2)  (2 x + 1)

sedatefrog712 · Answer

ok so max left out the 2 right

directrix · Answer

Ann factored it as 2(x − 2)(2x + 1) and Max factored it as (x − 2)(4x + 2).

Ann factored it correctly and completely.

Max's factoring is correct but is not complete because as you said, he could have factored out another 2.

sedatefrog712 · Answer

oh ok thank you so very much @Directrix it makes a lot more sense now :D

directrix · Answer

You are welcome.