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Mathematics 8 Online
OpenStudy (anonymous):

Please help just number 4 (:

OpenStudy (dayakar):

what is the question

OpenStudy (anonymous):

I just am not sure how to do it

sammixboo (sammixboo):

But what is the qquestion? :P

OpenStudy (anonymous):

Oh you can't see the picture??

OpenStudy (anonymous):

The question is determine whether each relation is a function. Find the domain and range 4.{(4,5),(1,5),(3,8),(4,6),(10,12)}

OpenStudy (bibby):

a relation is a function if it has one x for every y. that means we can't have repeated x values. do we?

OpenStudy (dayakar):

in other words, each first coordinate (x) is different ,it is called a function

OpenStudy (anonymous):

Yes there is so its not a function correct?

OpenStudy (dayakar):

exactly

OpenStudy (anonymous):

Thank you (: and how do I find the domain and range?

OpenStudy (dayakar):

domain=set of all first co-ordinates

OpenStudy (dayakar):

range= set of all second co-ordinates

OpenStudy (anonymous):

So add all the x values?

OpenStudy (anonymous):

And then add all the y values? Or do I multiply

OpenStudy (dayakar):

no,write all first co-ordinates separate with commas

OpenStudy (dayakar):

can u write

OpenStudy (anonymous):

All I have to do is write the x values and the y values? That's so easy what the heck lol

OpenStudy (dayakar):

show ur work

OpenStudy (anonymous):

Domain : 4,1,3,4,10 Range:5,5,8,6,12

OpenStudy (bibby):

no repeats, as far as I know

OpenStudy (dayakar):

no

OpenStudy (anonymous):

Oh so don't put 2 of the same numbers correct?

OpenStudy (dayakar):

D={1,3,4,10} no,element repeated in a set

OpenStudy (anonymous):

Therefore Domain: 4,1,3,10 Range: 5,8,6,12

OpenStudy (dayakar):

get it write range and show

OpenStudy (dayakar):

very good

OpenStudy (anonymous):

It matters what order they r in?

OpenStudy (bibby):

least to greatest

OpenStudy (dayakar):

order is not not important

OpenStudy (dayakar):

for our convenience we write in order

OpenStudy (dayakar):

put { }

OpenStudy (dayakar):

is it clear

OpenStudy (anonymous):

Okay thank you very much!

OpenStudy (dayakar):

welcome

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