Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?
5,–1, –7, –13, –19, ...
f(n + 1) = f(n) + 6
f(n) = f(n +1) – 6
f(n +1) = f(n) – 6
f(n +1) = –6f(n)
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OpenStudy (freckles):
look at the terms what is happening?
OpenStudy (freckles):
like is there a common difference?
OpenStudy (freckles):
if so what?
OpenStudy (karolynxx):
It's going down -6 each time right ?
OpenStudy (freckles):
which one of the recursive formulas shows that...
that is which one shows term=previous term - 6
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OpenStudy (karolynxx):
B , C , D right now
OpenStudy (freckles):
no not all of those show that
OpenStudy (karolynxx):
I believe its B .
OpenStudy (freckles):
f(n+1) is a term
what is the term previous to f(n+1)?
OpenStudy (karolynxx):
Oh C!
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OpenStudy (freckles):
yes if f(n+1) is a term in the sequence then the previous term to it is f(n)
and we were looking for the one that said term=previous term-6
so that is f(n+1)=f(n)-6
OpenStudy (freckles):
you can even verify if you want plug in n=1 and and see if you get f(2) is -1