Question

part d
https://www.dropbox.com/s/84fwguydxb06oqr/Screenshot%202015-11-12%2012.50.13.png?dl=0

Answer 1

Looking for a derivation / explanation...

Answer 2

Here are my answers for other parts

part b :
\(\dfrac{F}{m+M}\)


part c :
\(M*\dfrac{F}{m+M}\)

Answer 3

@baru

Answer 4

@lochana

Answer 5

my understanding of tension is poor...b) and c) says neglect sagging,

so straight away we can say that the rope and block should have the same acceleration,
so a=F/(M+m)

and F=m*a for (c)

am I missing something?

Answer 6

M*a for (c)

Answer 7

I think it is
\[T = \frac{FM}{m+M}\]

Answer 8

here we get acceleration
\[a = \frac{M}{m+M}\]

Answer 9

it's \[a = \frac{F}{m+M}\]

Answer 10

now we can divide this system into two parts and consider rope with its extensional forces