help?
for those that don't want to download an rtf find the equations for each table and then find the solution
to start, let's do line 1. we're going to use \(y-y_1=m(x-x_1)\) we need to find m using the slope formula
okay so the slope would be -3 for line 1 yes?
correct, then we need an \((x_1,y_1)\) so we just pick either point in the table \(y-9=-3(x-(-1)) \\y-9=-3(x+1) \\y-9=-3x-3 \\y=-3x+6\) do the same thing for line 2, then we can set them equal to each other to find the solution
find the slope of line 2?
yeah, then put it into point slope form
the slope is 2 iknow that lol
and let me do the other part , one moment
y-(-5)=2(x-2)
yeah?
I guess it's not that necessary to do point slope form cause you can just find the y intercept (the place where x=0) by adding 2 to the first point close \(y-5=2(x-2)\)
ya so now i solve that?
yeah
ok i got y=2x-6 therefore the y intercept is -6... yea?
the y intercept should be 1, let me see what happened \(y-5=2(x-2) \\y-5=2x-4 \\y=2x-4+5 \\y=2x+1\)
so we want the solution to the following equations \(y=-3x+6,\\ y=2x+1\) do you know how to do that?
ill explain hoe im got what i did y-(-5)=2(x-2) y+5=2x-1 -5 -5 ________________ y=2x-6
I'm no hoe : (
how****
im sorry lmao
hahaha I said 5 btw, not -5 we if the point on the table was (2,-5) then your equation would be right
so my equation is wrong?
yeah. \(y-y_1=m(x-x_1)\\(x_1,y_1)=(2,5)\\m=2\) alternatively you can try it with x1,y1=(-1,-1)
ugh i hate math this is so confusing.. thank you for helping me.... but what is the anser
answer*
I already said the equation to line 2 is \(y-5=2(x-2) \\y-5=2x-4 \\y=2x-4+5 \\y=2x+1\) so now we have \(y=2x+1\\y=-3x+6\) can you find the solution to that?
would i now substitute?
mhm \(-3x+6=2x+1\) solve for x, replace in one of the original equations to find the y
so i did 2x+1 =y therefore x=y-.5 yes?
eh, that's kind of unnecessary, we already have them both in terms of y, so we can just substitute in straight away |dw:1447347508697:dw|
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