Please help I have tried every single one of these equations and I cant seem to get it right. The width of a rectangle is 4 less than one-half its length. If the perimeter is 70 cm, identify the equation for the problem, then use it to find the length. Select two answers. 2(2l)+2(-4)=70 25 cm 2(l +1/2l - 4)=70 26 cm 2(l + 4l - 4/2)=70 21 cm 35 cm 2(2l)+2(4)=70
`he width of a rectangle is 4 less than one-half its length` translate this into math equation
the**
w= 1/2L?
hmmm there is a mistake the width of a rectangle is `4 less than one-half` its length
oh sorry w=1/2l-4
alright and what's the equation we should use to find perimeter of rectangle ?
2(l +1/2l - 4)=70
I tried it but I cant get the right answer
alright no the original equation is \[\huge\rm P=2L +2w\] that suppose to be our 2nd equation replace p with given perimeter which is 70
and then use substitution method
substitute for l and w?
\[\rm\color{ReD}{ w=\frac{1}{2}L-4}\] first equation^\[\rm2L+2\color{ReD}{w}=70\] 2nd equation^ so replace w with first equation
2L+2(1/2L-4)=70?
correct solve for l
L**
ok one second:)
I got like 37.5...
looks like you did the same mistake i was doing few sec ago
show me how did you get that ?
haha okay at least i wasnt too far off
umm so I distributed the two and then added like terms which resulted in 2l+3-8=70 which turned into 2l=75 and then i divided...
and how did you get 3 there ??
well there is a mistake with distribution \[2(\frac{1}{2}L-4)\] 2 times 1/2l = ?
1
not just one oh well let me retype it 2 times 1/2L
I meant 1l
\[\rm 2l+2(\frac{1}{2}L-4)=70\] \[\rm 2L+1L-8=70\] you should get 1L instead of 3 now combine like terms that's it:=)
oooh okay. thank you so much!
np :=)) good work!
thank you! and thanks for being patient with me haha. @Nnesha
my pleasure!
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