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OpenStudy (anonymous):
OpenStudy (anonymous):
Anyooooone? It's due soon
OpenStudy (anonymous):
Too much reading effort LOL... but fine ill help ish
OpenStudy (anonymous):
I know! And thanks
OpenStudy (anonymous):
The first one is law of sines.
SinA/a=SinB/b
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OpenStudy (anonymous):
or let me write that more clearly...
(Sin(A))/a=(Sin(B))/b
OpenStudy (anonymous):
where A and B are the angles
OpenStudy (anonymous):
and a and b are the side lengths.
OpenStudy (anonymous):
you have all the numbers so just plug and chug
OpenStudy (anonymous):
for the second part you need to use the law of cosines to find either angle C or sidelength c
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OpenStudy (anonymous):
a^2=(b^2+c^2)-2bc*cos(A)
OpenStudy (anonymous):
again you have all the numbers so just plug and chug.
OpenStudy (anonymous):
(oh and the two possible values come from two possible interpretations of sin)
OpenStudy (anonymous):
(so basically you need to use the law of cosines twice or something)
Finding the areas
A=(1/2)*a*b*sin(C)
OpenStudy (anonymous):
basically ive given you all the formulas, all you need to do is plug and chug and remember that there are two possible values when you do the arc sin in the initial part of the problem.
So yeah you should be able to do it.
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OpenStudy (anonymous):
I need to go write my 5 page essay due tomorrow so gl!