Question

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Answer 1

What is the solution?

Answer 2

start by multiplying both sides by 3

Answer 3

What are the sides? XD

Answer 4

both sides of the equation...

Answer 5

you have the left side of the equal sign, which is the n(-2n-2)/3 part
and the right side, which is the 12

now multiply both sides by 3

Answer 6

12=36. But how do i do the first one?

Answer 7

when you multiply the expression by 3, the 3 in the denominator cancels out

Answer 8

now we set that equal to 36 and solve for n

Answer 9

next, distribute the n on the left side

Answer 10

Im stuck..!! everything made sense but i don't get the (-2n-2) part.

Answer 11

apply the distributive property

A(B-C) = A*B - A*C

n(-2n-2) = ?

Answer 12

n=0 ????

Answer 13

no, I'm not asking you to solve for n, I'm asking you to rewrite the expression

Answer 14

n*(-2n) = ?

Answer 15

-2n= n?????????????????? omg :o IM SO CONFUSED ON WHAT TO DO HERE!!!!

Answer 16

just multiply them together...

Answer 17

I may be doing my math wrong, but wouldn't it equal -2n^2?

Answer 18

I don't know what n is though? So how could i multiply n and that?

Answer 19

we can still multiply n by n to get n^2, like duck said

Answer 20

(n)*(-2n) = -2n^2

Answer 21

Ohhhh so it equals -2n^2?

Answer 22

we can perform math operations on variables without knowing what the variables are

like, how x + x = 2x

Answer 23

yes, (n)*(-2n) = -2n^2

now multiply (-2) and n

Answer 24

-2*n= n? >_<

Answer 25

-2*n is just -2n

Answer 26

Ohhh. Okay... So that's all?

Answer 27

now we keep going

n(-2n-2) = -2n^2-2n after we apply the distributive property

Answer 28

then divide both sides by 2

Answer 29

36 divided by 2 = 18. So what is the next one i divide?

Answer 30

don't forget the left side

Answer 31

2n?

Answer 32

Just a suggestion... wouldn't you want to square root both sides before dividing?

Answer 33

why would I take the square root?

Answer 34

Isolation of the variable n, when you have 2n^2, It'd be easier to square root it in the beginning, while you still have a perfect square..

Answer 35

I may be wrong, but that's just how I saw that.