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Please help me!!!!! (-27x^3+54x)/9x
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\[\frac{-27x}{9x} + \frac{54x}{9x}\]
can you do it now. something will cancel out
Is that simplified?
you missed x^3 in the numerator
ah yes. sorry about that
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so \[\frac{-3*x^29x}{9x} - \frac{6*9x}{9x}\]
9x go away
I'm confused...
and you get -3x^2-6
-27x^3 is -3.x^2.9x okay?
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\[-27x^3 =-3.x^2.9x\]
okay
and\[54x = 6.9x \]
so \[\frac{-27x^3 + 54x}{9x} = \frac{-3.x^2.9x + 6.9x}{9x} = -3x^2 + 6\]
and i did another mistake in my last answer. it should be +6. not -6
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still confused?
call me back if you are still confused. type @lochana
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