Will fan and Medal! Solve the equation, x^3x-1=(e^6)^-x
\[x=\ln(x)/3(\ln(x)+2)\]
So what would the answer be?
well are you suppose to solve for x?
I'm assuming...because it only said solve for x.
then that is the answer
I'm sorry i mean that it only said to solve the equation.
well im pretty sure that it is still that answer
The answers possible are, A.) -1/3 B.) 0 C.) 1-9 D.) 7/4
C is actually 1/9
Can you re-write it using equation button ?
How do you do it? I don't see the equation button.
\[x^{3x-1}= e^{-6x} \] this ? Down, you will see Equation, draw, Attach file buttons, near "Post" button
Yes that is it except for the 6 in the power is in () with the e and the -x is still in the power but outside of the ().
My thing only says, post it doesn't have anything else.
(2^2)^2 = 2^4 so the powers are multiplied.
It's like e^6 are in ( ) and then -x is ^the power but outside of the ( )
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