Find the equation of the line that fits the description. Passes through (6,−1) and has zero slope.
In what form? Point slope? Slope intercept?
ok so if slope is 0 the line will have form y=a. lines with 0 slope is horizontal. |dw:1447397515978:dw|
@AlexandervonHumboldt2 it says equation.
i know
Passes through (6,−1) and has zero slope. y=mx+b. m=0 substitute your point: -1=6*0+b b=-1
b is y-intercept, thus the equation will look like y=-1
Please do not give the answer.
so when it asks for the equation of a line would i give an answer of -1=6(0)+b or I am confused
We can do this another way i am confused by the way alex did this... I personally perfer the point slope method either way we get the same answer \[\huge y-y_1=m(x-x_1)\] where m=slope (x1,y1)
Can you plug in the info the formula?
what confused way? we have that slope =0 and y intercept is -1. y=mx+b y=0*x-1 y=-1
y-1=0(x-6)
then add 1 both sides and y=1
No first distribute the 0
distributing 0 is 0 right?
Yes
so its y-1=0 then you add 1 to both sides and y=1
You didnt plug in a coordinate right
y+1=0(x-6) Remeber that a neg + neg= pos
And now what will your answer be y=?
y=-1
Correct well done :)
so when it asks for a equation how do i put it?
y=-1 is your equation its a horizontal line
oh okay thanks!!
:)
No problem =)
Hey pooja195 would you help me at http://openstudy.com/study#/updates/565cf04ee4b0603f58e8dce6?
PLease???
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