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Mathematics 8 Online
OpenStudy (anonymous):

The hourly salary of five workers are $6, $6, $8, $10, and $35. Is the mean or median the best measure of center to summarize the salaries of the workers?

OpenStudy (anonymous):

@EKKERKING

OpenStudy (anonymous):

help

OpenStudy (anonymous):

@Tamara7301

OpenStudy (anonymous):

@mas6xavi

OpenStudy (anonymous):

HELP

OpenStudy (anonymous):

I THINK IT IS BOTH mean AND median

OpenStudy (anonymous):

median

OpenStudy (anonymous):

are you sure

OpenStudy (tamara7301):

i think hes right

OpenStudy (anonymous):

A. mean B. median C. Both mean and median summarize the data equally well.

OpenStudy (anonymous):

Yes sure.. we use the mean only when the data is symmetrical

OpenStudy (anonymous):

thanks

OpenStudy (♪chibiterasu):

The problem is that there is a very different amount of 35$ which would give a really weird average. (mean) 35 + 10 + 8 + 6 + 6 = 65 65/5 = 13 13$ is higher than all but the 35$ salary.

OpenStudy (anonymous):

in this question 35 is greater number so if we use mean... the result would be 13, which is no actual summary of data in the other hand median will be 8 which actually represents and summarize data better

OpenStudy (♪chibiterasu):

I'm so dumb I put the $ after the numbers :|

OpenStudy (♪chibiterasu):

But w/e you get the idea

OpenStudy (anonymous):

Yup 35 is called outlier in this case

OpenStudy (♪chibiterasu):

Like mas6xavi said, an outlier will highly affect data so the median is a better source of average.

OpenStudy (anonymous):

so the answer is median

OpenStudy (♪chibiterasu):

That would be the best option yes

OpenStudy (anonymous):

thanks and bye

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