Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Can anyone help with factoring polynomials?

OpenStudy (anonymous):

Factor completely: 5ab(x + 6) − 4(x + 6) Select one: a. Prime b. (x + 6)(5ab + 4) c. (x + 6)(ab) d. (x + 6)(5ab − 4)

Mehek (mehek14):

what do you think?

OpenStudy (anonymous):

im not sure

OpenStudy (anonymous):

where to start

OpenStudy (baru):

do you know how to expand this (a+b)(c+d)

OpenStudy (anonymous):

ac + ad + bc + bd ?

OpenStudy (baru):

yes!!

OpenStudy (baru):

is this how you did it? (a+b)(c+d) =a(c+d)+b(c+d) =ac+ad+bc+bd

OpenStudy (anonymous):

yes :)

OpenStudy (baru):

now look closely at the second step a(c+d)+b(c+d)

OpenStudy (anonymous):

ac + ad + bc + bd?

OpenStudy (baru):

no...i asked you to expand. your question is asking you to go in reverse (factorize) the question resembles a(c+d)+b(c+d) go reverse to get back (a+b)(c+d)

OpenStudy (anonymous):

Walk me through this please... confused :/

OpenStudy (baru):

(m+n)(p+q) =m(p+q)+n(p+q)

OpenStudy (baru):

you get what i just did there?

OpenStudy (anonymous):

not really...

OpenStudy (baru):

how did you expand (a+b)(c+d) ?

OpenStudy (anonymous):

Multiplid everything

OpenStudy (baru):

do you know "distributive property of multiplication over addition"?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!