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OpenStudy (anonymous):
Factor completely: 5ab(x + 6) − 4(x + 6)
Select one:
a. Prime
b. (x + 6)(5ab + 4)
c. (x + 6)(ab)
d. (x + 6)(5ab − 4)
Mehek (mehek14):
what do you think?
OpenStudy (anonymous):
im not sure
OpenStudy (anonymous):
where to start
OpenStudy (baru):
do you know how to expand this
(a+b)(c+d)
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OpenStudy (anonymous):
ac + ad + bc + bd
?
OpenStudy (baru):
yes!!
OpenStudy (baru):
is this how you did it?
(a+b)(c+d)
=a(c+d)+b(c+d)
=ac+ad+bc+bd
OpenStudy (anonymous):
yes :)
OpenStudy (baru):
now look closely at the second step
a(c+d)+b(c+d)
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OpenStudy (anonymous):
ac + ad + bc + bd?
OpenStudy (baru):
no...i asked you to expand.
your question is asking you to go in reverse (factorize)
the question resembles a(c+d)+b(c+d)
go reverse to get back (a+b)(c+d)
OpenStudy (anonymous):
Walk me through this please... confused :/
OpenStudy (baru):
(m+n)(p+q)
=m(p+q)+n(p+q)
OpenStudy (baru):
you get what i just did there?
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OpenStudy (anonymous):
not really...
OpenStudy (baru):
how did you expand (a+b)(c+d) ?
OpenStudy (anonymous):
Multiplid everything
OpenStudy (baru):
do you know "distributive property of multiplication over addition"?