Question

Stuck on a novice vector problem, I keep getting it wrong so I may be doing something wrong.

Answer 1

\[-3(3X+2U)+2V=-V-2U-3X\]
\[-9X+6U+2V=-V-2U-3X\]
TAKING COMMON TERMS TO EACH SIDE
\[6U+2V+V+2U=9X-3X\]
\[8U+3V=6X\]
\[\frac{ 4 }{ 3 }U+\frac{ 1 }{ 2 }V=X\]
Am I doing this right?

Answer 2

@zepdrix

Answer 3

Small correction to make on second step,\[\large -9X\color{red}{+}6U+2V=-V-2U-3X\]

Answer 4

I dont understand why is it red?

Answer 5

is it suppose to be a negative?

Answer 6

oh right it is

Answer 7

Ya I guess negative when you distribute :)

Answer 8

I got \[\frac{ -2 }{ 3 }U+\frac{ 1 }{ 2 }V=X\]
Now I just plug the vectors in and solve for x right?

Answer 9

I would leave it in the unreduceded form because you have to combine fractions anyways
well I mean I assumed you solved it the same way as me so you know what I mean by unreduced form but it is possible you didn't solve it like me :p

Answer 10

so you wouldnt recommend taking 6 to the other side and then solving it? will that change the answer?

Answer 11

Ya I would agree,
I think it's probably easier to simplify everything in the brackets before you apply the 1/6,\[\large\rm \frac{1}{6}\left(-4U+3V\right)=X\]Doesn't matter though :)

Answer 12

^

Answer 13

ok let me do that

Answer 14

this is what I have so far