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help how do i integrate the following
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\[\frac{ 4r }{ \sqrt{1-r ^{4}} }\]
tried integration by parts but it just kept looping, looked at model answer and does not know what is happening
Have you tried subing \(u=r^2 \) ?
no, thats the given ans's step as well but after subing u=r^2 the numerator would be troublesome wouldn't it?
\[\frac{ 4\sqrt{u} }{ \sqrt{1-u ^{2}} }\]
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hold up, not so fast
with \(u\) substitution, you need to replace both \(r\) and \(dr\)
\[\int \frac{ 4r }{ \sqrt{1-r ^{4}} }\, dr\] thats your integral, right ?
oh.. ok i think i understand my mistake now give me a sec i will try with this new information
okie good luck!
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k i got the ans thanks
np :)
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