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Mathematics 16 Online
OpenStudy (kristenskate):

HELP ASAP WILL FAN AND MEDAL

OpenStudy (kristenskate):

At 5:00 p.m., Antonio turned on the oven. While the oven preheated, the temperature in the oven increased from 72°F to 400°F over a 10-minute period. The oven remained at 400°F for 45 minutes until Antonio turned it off. It took 60 minutes for the temperature in the oven to cool, returning to 72°F at 6:55 p.m. Which statement best explains whether or not the temperature in the oven is a function of the time? A. It is a function because at any given time the oven was exactly one temperature. B. It is a function because the oven temperature was the same at different times. C. It is not a function because at any given time the oven was exactly one temperature.

OpenStudy (kristenskate):

I took the answer i knew were wrong please help!!

OpenStudy (anonymous):

In this case, what would you consider your Y and X axis to be? Also what test do you do to see if something is a function or not?

OpenStudy (kristenskate):

A function can be identified on a graph using the vertical line test..

OpenStudy (kristenskate):

@Gerardo_cast23

OpenStudy (anonymous):

Yep Exactly! So what is your x-variable, and what is your y-variable? I ask this so that we can create a hypothetical graph of the scenario in the question,

OpenStudy (kristenskate):

time would be my x and F ˚ would be my y

OpenStudy (kristenskate):

@Gerardo_cast23

OpenStudy (kristenskate):

I think the answer is B... is that correct? @Gerardo_cast23

OpenStudy (anonymous):

Nope :/

OpenStudy (kristenskate):

it has to be A then.. because its a function!!

OpenStudy (kristenskate):

right...?

OpenStudy (anonymous):

|dw:1447729623863:dw|

OpenStudy (anonymous):

Haha yes by process of elimination yes it is A

OpenStudy (kristenskate):

yay!!

OpenStudy (anonymous):

But if we look above, that is sort of how it looks like. The temperature increases, stays the same, then decreases. Now read the options and A makes sense. Try to draw pictures and it should help in these kinds of problems

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