Question

k^2+5k+6=(k+2)(k+[])
A.3
B.6
C.12
D.4

Answer 1

what are you trying to find

Answer 2

since the leading coefficient is one
find two numbers when u multiply them you should get product of AC(a=leading coefficient , c=constant) and when add/subtract them you should get the middle term

Answer 3

k^2+5k+6 = (k+2)(k+[])

(k + 2) (k + 3) = (k+2) (k+[])

The (k + 2) factors divide out.

(k + 3) = (k+[ ? ])

@biggirl99