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Mathematics 17 Online
OpenStudy (anonymous):

multiple choice answers.

OpenStudy (anonymous):

OpenStudy (anonymous):

i believe it is a

OpenStudy (anonymous):

if there are 4 suits out of 52, how would you figure out that ratio?

OpenStudy (anonymous):

do I have to simplify it?

OpenStudy (anonymous):

it is d im pretty sure

OpenStudy (cresciez):

If you simplify it, you would get 2/13 making it choice C ~

OpenStudy (anonymous):

52/4 ( to find overall number of clubs) then +4 ( to find the kings) there fore is 17

OpenStudy (cresciez):

Tbh this is a very logical question - people think you have to think about it very hard. But really you don't - there are 4 suits out of 52 right? Take those, make it into a fraction, and simplify it - at least I believe this is the answer. :P

OpenStudy (anonymous):

its a club or a king... that increases search perameters, dont forget that

OpenStudy (cresciez):

Good luck @vzfreakz <3 Whatever choice you make I hope it works for you :)

OpenStudy (anonymous):

looking for chance of clubs and chance of kings combined not for each suit

OpenStudy (anonymous):

btw, if you simplify 4/52 it is 1/13, which isn't even a choice!

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

we have: probability to get a club = 13/52 probability to get a king = 4/52= 1/13 so, the requested probability is: \(13/52 + 4/52=...?\)

OpenStudy (anonymous):

17/52

OpenStudy (anonymous):

I have more questions like this. Can you still help? I only have three more @Michele_Laino

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

correct! it is 17/52

OpenStudy (anonymous):

OpenStudy (anonymous):

how about this one? ^

OpenStudy (michele_laino):

probability to get a prime number is: \(5/12\) since we have \(five\) prime numbers: \(2,3,5,7,11\) probability to get an odd number is: \(6/12=1/2\), since we have \(six\) odd numbers: \(1,3,5,7,9,11\) so, requested probability: \(5/12 + 6/12=...?\)

OpenStudy (anonymous):

11/12

OpenStudy (anonymous):

I'm getting it so far.

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