Solve the following system by substitution y=x-1 y=-4/3x-8 A. 4,3 B. 3,4 C. -4,-3 D.-3,4
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\[\huge~\rm~x-1=\frac{ -4 }{ 3 }x-8\] Solve for x I plugged equation 1 into equation 2
So then if you substitute you get -16/3 but it not equal to -8
Now quite... \[\huge~\rm~x-1+4/3=\frac{ -4 }{ 3 }x+4/3-8\] \[\huge~\rm~\frac{ 7 }{ 3 }x-1=-8\] \[\huge~\rm~\frac{ 7 }{ 3 }x-1+1=-8+1\] \[\huge~\rm~\frac{ 7 }{ 3 }x=-7\] Now solve for x
i think you have all the help you need she seems to be doing great
achuley perfect
Thanks! =)
If you plug 4 for x right because u use the first problem
Now we are only solving for x
For right now
yea you are very good at math
But then how do use substition method
\[\huge~\rm~\frac{ 7 }{ 3 }x \div \frac{ 7 }{ 3 }x=-7 \div \frac{ 7 }{ 3 }x\]
Did you look at the steps I wrote out above?
Don't you plug the first plug 1 into 2
It doesnt matter how you plug them in....you sill get the same answer
\[\huge~\rm~x=-7 \div \frac{ 7 }{ 3 }x\]
Yea you added-4/3 to both sides
We are way past that...
I got -1/3 but
For x
Thats incorrect What is -7 divided by 7/3 ?
Oh it's -3
Oh ok I get it know so then it is d right
@pooja195
My bad answer d was suppose to be -3,-4
Does that change anything
D is correct correct =)
What do you mean by "Does it change anything?"
But the 4 in d I forgo to put - sign in front of the 4
That's why I was asking if it changes anything
We know that x=-3 right We can substiitue the value of x into y=x-1 \[\huge~\rm~ y=(-3)-1\] \[\huge~\rm~ -4=(-3)-1\] So -3-1=-4 therefore y=-4
@taylor0402 thank you anways
Oh ok thank so much you been do patient with me @pooja195
It d then
haha no problem ^-^ Our goal is to help users understand =) their question patience is the virtue! Yes correct it is D :)
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