Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = 1/4 (x – 12). What is the standard form of the equation for this line?

a. x – 4y = 8
b. x – 4y = 2
c. 4x – y = 8
d. 4x – y = 2

Answer 1

multiply both sides with 4

Answer 2

can u do it

Answer 3

4y-4 = 4*1/4(x-12)
4y-4 = x-12
add -4y both sides

Answer 4

makes no sense to me

Answer 5

-4y+4y-4 = x-4y-12
-4 = x-4y-12
add 12 both sides
12-4 =x-4y-12+12
8 = x-4y
x-4y=8
answer is a

Answer 6

Here's an example of how to get to standard form! :)

Answer 7

Thank you!