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pre-calc
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\[ y= \frac{x^2 + 3x-4}{x+4}\] you can factor the top into (x-1)(x+4) \[ y = \frac{ (x-1)(x+4)}{(x+4)}\]
you are not allowed to divide by 0, x+4 is zero if x is -4 so at x=-4 you should have a "hole" to show we can't plot anything there
could you graph it for me as an example please??
for all other x's (x+4) is not zero, so we can simplify (x+4)/(x+4) to 1 and the graph is y= x-1
so would the graph look like this:
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|dw:1447946800728:dw|
coordinates (-4,5)
(-4,-5)
yes, a straight line with slope 1, with y intercept -1 and a hole at (-4,-5)
ok! could you please help me with one more
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The hard part is factoring the quadratic
yeah true!
can you help me with one more please?
please make a new post
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