Question

What is the vertex form of the equation
y=-x^2+12x-4
I am looking for help. I need to know step by step how to do it.

Answer 1

@bibby can u help

Answer 2

can you complete the square

Answer 3

@Crazymoron

Answer 4

are you in connections academy?

Answer 5

im stuck on this problem to so i can not help sorry

Answer 6

I figured I'd try helping the both of you in one problem

Answer 7

y = x^2 + 12x - 4
y = x^2 + 12x + (36 - 36) - 4
y = (x^2 + 12x + 36) - 36 - 4
y = (x + 6)^2 - 40

@Crazymoron

Answer 8

\(y=-x^2-12x+4\\y=-1(x^2+12x-4)\\y+36=-1(x^2+12x+36-4)\\y+36=-1((x+6)^2-4)\\y+36=-(x+6)^2+4\\y=-(x+6)^2-32\)

Answer 9

is this wrong?

Answer 10

yeah the 4 is negative in the equation

Answer 11

i did it totally different. i used method 2 on this website http://mathbitsnotebook.com/Algebra1/Quadratics/QDVertexForm.html
so i ended up geting Y=-x(x-6)^2-40

Answer 12

the x^2 is negative

Answer 13

i know. i did everything the same

Answer 14

as it was on the website

Answer 15

@kimbllse777

Answer 16

this is how I solved it.... Hope it is right...