help me understand what exactly what i'm looking for
Which line is a graph of the equation: 2x + 5y = –10?
You're given the equation of a straight line and are asked which of the graphed lines matches the equation you're given. You might start by solving 2x + 5y = -10 for y (but this is not the only way in which you could approach this problem).
If you do solve for y here, your resulting equation will have the form y = mx + b, where b is the y-coordinate of the y-intercept, and m represents the slope (rise/run). Is your slope positive or negative?
@mathmale positive
@mathmale exactly how do i solve for Y
@superdavesuper how do i solve for y
You have 2x + 5y = -10. Want this transformed into the form y = mx + b. Since you want x on the right side of the eq'n, subtract 2x from both sides of 2x-5y=-10.
so i will make the problem 5y=-10-2x @mathmale
5y=2x+10 check your simplification
@dan815 i thought if iswiched it to the other side of the equal cign it would become a _negative
am i wrong @dan815
okay so i got 5y=2x+10
what do i do next
Actually, your result (from 2x + 5y = –10) should be 5y = -2x -10. Try doing this yourself . Then we can move on.
y=mx+b 1s the 3quat10n 0f å l1ne.
@Watermelon_Talk : Again, please subtract 2x from both sides of this equation. Simplify the result. Write your final result here. Be careful with your signs.
5y=10 to y=2 am i right @mathmale
Your original 2x + 5y = -10 becomes 5y - 2x -10. Dividing every term by 5 produces the equation in slope-intercept form. We get (5/5)y -(2/5)x -2, or \[y=\frac{ -2 }{ 5 }x-2\]
Thus, the slope of the graph of this line is -2/5, and the y-intercept is -2 (or (0,-2).
Please go back to the illustration that came with this problem. Because we've found that the slope of the given line is negative: -2/5, we can eliminate any and all of the blue lines that have positive slopes. You will have several blue lines left. Now decide which one of them has a y-intercept of -2 (that is, which line passes through (0,-2).
aghh im so confused i have a head ache now
but i think i got it up to the the step after the 5y=-2x+10 @mathmale
2x + 5y = –10 So you subtracted 2x on both sides, mhmm? 5y = -2x - 10 Not sure how you changed it to a +10
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