If sinx=4/5 and x is in quadrant 2, then tan2x=
-12/7
24/7
-24/7
12/7
I tried solving using a 3-4-5 triangle and got some answers that were very off. PLEASE HELP
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OpenStudy (cutiecomittee123):
I am pretty sure we have to use trig identities. I am not sure if we use sin2x or tan2x double identities to solve, or if it is totally different identities from that.
OpenStudy (welshfella):
draw the triangle in quadrant 2 first
|dw:1447970367311:dw|
OpenStudy (welshfella):
so tan x = -4/3
now you can use the formula for tan 2x
= 2 tan x
-------
1 - tan^2 x
OpenStudy (welshfella):
(if my memory serves me right)
OpenStudy (welshfella):
i'll check that out
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OpenStudy (welshfella):
yea thats correct
so plug in tanx = -4/3
OpenStudy (cutiecomittee123):
so tan2x=2tan-4/3/1+tan2(-4/3)
OpenStudy (welshfella):
no
tan 2x = (2 * -4/3)
---------
1 - (-4/3)^2
OpenStudy (welshfella):
the -4/3 replaces the tan x
OpenStudy (cutiecomittee123):
why is the denominator squared?
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OpenStudy (welshfella):
(-4/3)^2 ?
use your calculator
OpenStudy (cutiecomittee123):
okay
OpenStudy (cutiecomittee123):
I get tan2x=3.43
OpenStudy (welshfella):
yes that is correct to 2 decimal places but they want the answer as a fraction
OpenStudy (cutiecomittee123):
24/7
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