Question

dy/dx for x^2 + y^2 = 2xy.

Answer 1

find y'?

Answer 2

i got 1

Answer 3

you can make this easy by -2xy on both sides...
\[x^2-2xy+y^2=0 \\ (x-y)^2=0 \\ x-y=0 \\ y=x\]

Answer 4

then find y'

Answer 5

and yes y'=1 since y=x

Answer 6

thank you so much!

Answer 7

np
you could find that y'=1 doing what I call the long way around :p

Answer 8

which is the way I bet you went about it