Question

PLZ HELP I WILL MEDAL AND FAN I HAVE TWO QUESTIONS PLZ! I WILL POST THEM NOW!

Answer 1

What is the solution to the system of equations?

2x + y = -3
x - 2y = -4

(__,__)

Answer 2

x - 2y = -4
Start by isolating x
add 2y to both sides
what are you left with?

Answer 3

i want and need to learn this, i just am confused here are just some random practice questions plz help thx

Answer 4

i am left with

x - 2y = -4 - 2y?

Answer 5

@pooja195

Answer 6

Ok wait lets start over
OK
So we need to isolate x so that we can solve using the substituion method :)
Start by adding 2y to both sides so that we have x alone
\[\huge~\rm~x - 2y +2y= -4+2y\]

Answer 7

ok now what i am writing this down

Answer 8

Well what are we left with?

Answer 9

x = 2y + 2y +2y + -4?

Answer 10

oh i mean
x = 6y + -4

Answer 11

oops*

Answer 12

o-o
not quite
x=2y-4
We cancelled out the 2y

Answer 13

oh oh oh, ok i thought i needed to add the 2y's up ok now what?

Answer 14

Now we have:
Equation 1
\[\huge~\rm~x=2y-4\]
Equation 2
\[\huge~\rm~2x + y = -3 \]
Now we can substitute Equation 1 into equation 2 BECAUSE we know that x EQUALS 2y-4
so like this:
\[\huge~\rm~2(2y-4)+y=-3\]
Can you solve for y?

Answer 15

yes one sec

Answer 16

y=1?

Answer 17

@pooja195

Answer 18

Correct

Answer 19

wait so what is x?

Answer 20

(_?_, 1)

Answer 21

Thats the next part! :)
Now we plug the y value into equation 1 =)
\[\huge~\rm~x=2(1)−4\]
solve for x

Answer 22

ok

Answer 23

x= -2?

Answer 24

@pooja195

Answer 25

is it (-2,1)

Answer 26

Well done :)

Answer 27

yay i have one more that needs checking

Answer 28

Ok :)