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Rewrite f(x) = –2(x − 3)^2 + 2 from vertex form to standard form
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good old vertex form :) Ok so the first step is distributing the (x-3)^2
why don't you do that
idk how
\[(x-3)^2 = (x-3)(x-3)\]
Your standard form must look like \[y=ax^2+bx+c\] where a,b and c are coefficients.
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look at what astro did, then multiply it all by -2, since that was the "a" coefficient
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